describe 'intersection' do
it { is_expected.not_to eq(nil) }
- it { is_expected.to run.with_params().and_raise_error(Puppet::ParseError) }
+ it { is_expected.to run.with_params.and_raise_error(Puppet::ParseError) }
it { is_expected.to run.with_params('one').and_raise_error(Puppet::ParseError) }
it { is_expected.to run.with_params('one', 'two').and_raise_error(Puppet::ParseError) }
it { is_expected.to run.with_params('one', 'two', 'three').and_raise_error(Puppet::ParseError) }
it { is_expected.to run.with_params(['one', 'two', 'two', 'three'], ['two', 'three']).and_return(['two', 'three']) }
it { is_expected.to run.with_params(['one', 'two', 'three'], ['two', 'two', 'three']).and_return(['two', 'three']) }
it { is_expected.to run.with_params(['one', 'two', 'three'], ['two', 'three', 'four']).and_return(['two', 'three']) }
- it 'should not confuse types' do is_expected.to run.with_params(['1', '2', '3'], [1, 2]).and_return([]) end
+ it 'does not confuse types' do is_expected.to run.with_params(['1', '2', '3'], [1, 2]).and_return([]) end
end